I've now just realized that perhaps the cracking_hook_call is not really 'hooking', but replacing the call itself. If that's the case, then this only makes sense if the function is called only from one place?
I've now just realized that perhaps the cracking_hook_call is not really 'hooking', but replacing the call itself. If that's the case, then this only makes sense if the function is called only from one place?
kung foo man (1st October 2019)