[C] The lousy random question thread

[serthy]

Hey, its me again..

		type foobar()
{
    return (type)1337;
}

class myClass
{
    public:
        type x;

        type foobar( float value )
        {
            type t = value * 2;
            std::cout << "type foobar( float value )" << std::endl;
            return t;
        }

        void foobar( float value )
        {
            x = value;
            std::cout << "void foobar( float value )" << std::endl;
        }
};

float tmp;
myClass c1 , c2;

foobar(); //calls function but returnvalue isnt used
tmp = c1.foobar( 42 );//calls methods
c2.foobar( 42 ); //does the compiler use the method without a returnvalue? 
	

i know that the compiler generates different function-identifiers for both methods (different in and output types)

but my question is: does the compiler/cpu know when to use a method with or without the returnvalue?



EDIT
maybe these console prints will brigthen things up